Comparison operators

Comparison Operators

Credits: illustration by unDraw

1. Why NaN isn't equal to NaN?


NaN === NaN; // false
NaN == NaN; // false


This behavior is specified by ECMA-262 in Strict Equality Comparison and Abstract Equality Comparison sections. In both comparisons, wheter strict (===) or not (==), if any of the operand is NaN the result is false. The pseudo code mentionned is as follows :

1. If Type(x) is different from Type(y), return false.
2. If Type(x) is Number, then
1. If x is NaN, return false.
2. If y is NaN, return false.

This is inherited from IEEE 754, the IEEE standard for floating-point arithmetic, which states that any operation performed on NaN should yield a false value or raise an error.

2. Why [] == ![] but [] == []?


[] == [] // false
[] == ![] // true
[] === [] // false
[] === ![] // false


With Javascript, comparing empty arrays (or any arrays) only returns true when the array is compared to itself. In the first example, two new empty arrays are created and compared. Since both values before and after the equal signs are implicitly declared and not referencing the same object, the comparison returns false.

A different behaviour in Javascript is that an empty array is considered a truthy value, thus converting an empty array to a boolean value returns true. In the second example, an empty array is compared to ![], which resolves to false. For the comparison, the first empty array is converted to its primitive value, which is an empty string (""). An empty string is considered a falsy value. The result is that a falsy value is compared to false, which returns true.

For the third example, two empty arrays are again implicitly declared and referencing two different arrays. This returns false as the references are checked are not equal.

The final example does a strict comparison against an empty array, thus an Array type, and ![], which once again resolves into true. Doing a strict comparison first checks both values' types, which are Array and Boolean here, and returns false if not equal.

3. Does the new String(...) makes any sense?


```js new String('foo'); // String {"foo"} typeof new String('foo'); // 'object' 'foo'; // 'foo' typeof 'foo'; // 'string'


new String('foo') == 'foo'; // true

TODO: explanation
## 4. How does x < y < z / x > y > z works?
> Example:
1 < 2 < 3; // true
3 > 2 > 1; // false


TL;DR:This is javascript way of evaluating above expressions and the reason for such wierd results Img

Generally the expression 3>2>1 is expected to return true since it is mathematically correct. But as javascript is a weak typed language, the evaluation of the above expression is done a bit differently. So lets break the evaluation down to 3 fundamental steps 1. ### Operator Precedence There are 2 operators(>,>) used in this expression (3>2>1) which have the same precedence. So the expression is evaluated from left to right as per Operator precedence table 2. ### Evaluation of left most expression The left most expression in 3>2>1 is 3>2. Javascript evaluates this expression and returns true as 3 is greater than 2. Hence we are left with the expression true>1 3. ### Implcit conversion Javascript now evaluates the left out expression i.e., true>1. As Javascript is weakly typed language, instead of throwing an error for operands of different types , it implicitly converts true to 1. So the expression is transformed to 1>1 which is obviously false. Hence the value is returned as false.

These are the steps that are followed to evaluate the expression and are the main reason for the weird results like the below ones

3>2>=1 //true
0<3<2 //true